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CAT | ELITMUS Quants Questions




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Q #36
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Quants Question

Directions: Read the following information to answer the question.

Read the following data to answer the questions given below Let f(x) be a function. fn(x) denotes function calculated n times, i.e. fn(x) = f(f(f……………n times (x))). So f3(x) = f(f(f(x))). It is defined that G1(x) = f(x) H1(x) = f2 (x) G2(x) = f2(x) H2(x) = f4(x) . . . . Gn(x) = fn(x) Hn(x) = f2n(x) If fn(x) = f2n(x) = , then Gn(x) >= Hn(x) for

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Q #37
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Quants Question

Directions: Read the following information to answer the question.

The graphs given in each question represent two functions f(x) and g(x) respectively. Mark your answer as

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As g (x) is reflected about x – axis. g(x) = -f(x)

Q #38
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Quants Question

Directions: Read the following information to answer the question.

The points of intersection of three lines, 2X + 3Y - 5 = 0, 5X - 7Y + 2 = 0, and 9X - 5Y - 4 = 0:

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Verifying option (1) is very cumbersome. Options (2) and (3) can be verified by expressing the lines

Q #39
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Quants Question

Directions : These questions are based on the data given below.

A book having 700 pages his its pages numbered from 1 to 700. If we count all the 3’s in the page numbers, how many 3’s will be there?

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Solution. From 1 to 100, we have number like 3, 13, 23, 33 etc. which are 10 in number. Then number 30 to 39 have one 3 extra each giving 10 threes. So, upto hundred, we have 10 + 10 = 20 threes. Since we have 700 pages we have number of 3’s as 7x20 = 140 Then all the 100 numbers from 300 to 399 have one 3 extra each giving a hundred 3’s So totally, 240 threes. Choice (1)

Q #40
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Quants Question

Directions : These questions are based on the data given below.

If two positive numbers a and b are such that a <50 and b >25, then which of the following can never be true? I.b > a II.2a – b < 0 III.3a + 2b > 200

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Solution. Statement I: Since a can take any value including those less than 25, this statement can be true. Statement II: By observation, we can make out that 2a-b can be less than zero. Statement III : 3a + 2b =3(50-k) + 2 (25+l) = 200 – 3k + 2l This can be grater than 200 since there is no restriction on the value if I where as k<50. Choice (4)