Let the number of watches required to be sold in the season be x. ? he sells (1500 - x) watches out of season. The expenditure for manufacturing 1500 watches is (1500 × 150) = 225,000. Add to this the fixed expenditure of Rs. 30,000. His total income is from x watches sold at 250 and (1500 - x) watches sold at 100. ? 2,55,000 = (250)(x) + (100)(1500 - x). Solving, we get x = 700.

The number of mints must be divisible by 3.

Let x be the number already contacted.

Then amount collected is 600 x.

As this is 75% of the sum, the total sum is 600x × 4/3  = 800 x.

Balance amount 200x has to be collected from 40%,

Hence  200x/0.4 x = 500.

Let the cost price of peanuts for the wholesaler be x per kg.

Cost price of walnuts for the wholesaler is 3x per kg.

The wholesaler sold 8 kg of peanuts at 10% profit and 16 kg of walnuts at 20% profit to a shopkeeper.

Total cost price to the shopkeeper = (8)(x)(1.1) + 16(3x)(1.2) = 66.4x The shopkeeper lost 5 kg walnuts and 3 kg peanuts.

The shopkeeper sold the mixture of 11 kg walnuts and 5 kg peanuts.

His total selling price=166(16) = 2656

?100 ?

His total cost price = 2656 ?    ? = 2124.8

66.4 x = 2124.8

x = 32

Price at which the wholesaler bought walnuts = 3x = 96/- per kg

Let no. of Fishes on earlier day = x
60 fishes are tagged, out of which 25% have died/moved
remaining fishes that are tagged = 45

No. of fishes on day of second observation = 5/4x
No. of fishes caught = 70
No. of Fishes tagged = 3 = 4.2857% (3/70)
Total No. fishes on Second day of Observation = 45/.042857 (45*70/3) = 1050

No of Fishes on earlier day = x = 4/5*1050 = 840