Directions: Read the following information to answer the question.
Let the pagadi amount be ‘p’
2/3 x (8400 + p) = 4500 + p
16800 + 2p = 13500 + 3p
p = 16800 – 13500
p = 3300
Directions: Read the following information to answer the question.
The total amount divided among the winners on the 1st week = 300 × x = 300 × 827 = 248100
Directions: Read the following information to answer the question.
Let the cost price of peanuts for the wholesaler be x per kg.
Cost price of walnuts for the wholesaler is 3x per kg.
The wholesaler sold 8 kg of peanuts at 10% profit and 16 kg of walnuts at 20% profit to a shopkeeper.
Total cost price to the shopkeeper = (8)(x)(1.1) + 16(3x)(1.2) = 66.4x The shopkeeper lost 5 kg walnuts and 3 kg peanuts.
The shopkeeper sold the mixture of 11 kg walnuts and 5 kg peanuts.
His total selling price=166(16) = 2656
?100 ?
His total cost price = 2656 ? ? = 2124.8
66.4 x = 2124.8
x = 32
Price at which the wholesaler bought walnuts = 3x = 96/- per kg
Directions: Read the following information to answer the question.
A got 36 marks but falls short of pass marks by 68%.
Maximum possible score is N.
Pass mark is 45% of N. 32% of 45% of N = 36 => N = 250
Directions: Read the following information to answer the question.
Let one pen, one pencil and one eraser cost n, p and r units respectively. Let the amount paid by me be A units.
∴ I pay (5n + 7p + 4r) = A ….. Eqn. (1)
& Rajan pays (6n + 14p + 8r) = 1.5 A … Eqn. (2).
Multiply equation (1) by 2.
we Get (10n + 14p + 8r)_ = 2A …….. Eqn.(3).
Comparing equations (2) and (3), we see that while Rajan gets 4 pens less, he pays 0.5A units less. Thus, A = the price of 8 pens. ∴ the % of the total price paid by me initially, which was used for pens is (5/8) (100) = 62.5%.