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Q #101
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Quants Question

Directions: Read the following information to answer the question.

Akshay and John started to dig a canal 10 km long. It is calculated that if Akshay takes off for 3 days, then John has to dig 1 km more and if John takes off for 4 days, Akshay has to dig n km more. Which among the following is true?

(a) If Akshay and John do the work without absence and Akshay digs 6 km, then the work gets completed in a little over 7 days
(b) n = 4/3
(c) If the work gets completed in 7.5 days, when Akshay and John dug without any absence, then Akshay dug 5 km
(d) all of the foregoing
(e) none of the foregoing


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Solution: Let W be the amount of work done in digging. Let Akshay, John do W/a and W/b parts of work per day respectively.
Let N, p, q be the number of days in which the work can be done if Akshay, John do the work together without absence, with Akshay absent for 3 days, with John absent for 4 days respectively. 

=> NW/a + NW/b = W, (p-3)W/a + pW/b = W and qW/a + (q-4)W/b = W.
Also, pW/b - NW/b = W/10 and qW/a - NW/a = nW/10. 
=> p = b/10 + N, q = an/10 + N
=> (b/10 + N-3)/a + (b/10 + N)/b = 1; (na/10 + N)/a + (na/10 + N-4)/b = 1
=> (b/10 - 3)/a + 1/10 + N(1/a + 1/b) = 1 and  n/10 + (na/10 - 4)/b + N(1/a+1/b) = 1, but N(1/a + 1/b) = 1
=> b/10 - 3 + a/10 = 0; and n/10(1/a + 1/b) = 4 => n = 4/3 and a+b = 30


Q #102
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Quants Question

Directions: Read the following information to answer the question.

A fill pipe can fill a tank in 20 hours, a drain pipe can drain a tank in 30 hours. If a system of n pipes (fill pipes and drain pipes put together) can fill the tank in exactly 5 hours, which of the following are possible values of n (More than one option could be correct)?

  1. 32
  2. 54
  3. 29
  4. 40


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3 fill pipes cancel out 2 drain pipes. Plus, you need an additional 4 fill pipes fill the tank in 5 hours. so the answer has to be 5k + 4. Both 54 and 29 are possible.

Q #103
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Quants Question

Directions: Read the following information to answer the question.

B takes 12 more days than A to finish a task. B and A start this task and A leaves the task 12 days before the task is finished. B completes 60% of the overall task. How long would B have taken to finish the task if he had worked independently(in days)?

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Let us say A and B split their share of the task and started doing their respective shares simultaneously.
Let’s say A takes A days to finish the task. Therefore, B takes A + 12 days to finish the entire task.
A has to finish 40% of the task, since B is doing the rest. So A will only take 2A/5 number of days.
B only has to finish 60% of the task, so B will take (3(A+12)/5) number of days.
But as we know, B starts working along with A and finishes 12 days after A stops working.
So, (3(A+12)/5) = ((2A)/5+12)
3A + 36 = 2A + 60
A = 24; B = 36 days.


Q #104
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Quants Question

Directions: Read the following information to answer the question.

A cistern of capacity 40 litres has an inlet and an outlet pipe. When both the pipes are opened at once, it takes 8 minutes to fill the cistern. However, if the outflow rate is increased 1.5 times, the cistern never gets filled. Which of the following can be the outflow rate?

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Initially, net flow in the tank = 40 litres/ 8 minutes = 5 litres/minute
Now, the increase in outflow should be greater than 5 litres/min for the tank to fill up.
Increase in outflow = 1.5x – x = 0.5x
Only in option C, 0.5 * 12 = 6 litres/min > 5 litres/min


Q #105
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Quants Question

Directions: Read the following information to answer the question.

Anuj, Bibhuti and Chandu can lay 432 m of wires together in 8 days. In a day, Chandu can lay as many more meters of wire than Bibhuti as Bibhuti can lay more than Anuj. Chandu’s 5 days of work is equivalent to Anuj’s 7 days of work. How many meters of wire can Anuj alone lay in a day?

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Length of wire all 3 of them can lay in a day = 432/8 = 54 m
On an average, 54/3 = 18 m will be laid by each which as per question should be the length Bibhuti can lay in a day.
Therefore, Anuj = 18 – x ; Chandu = 18 + x
Given,
7 * (18 – x) = 5 * (18 + x)
126 – 7x = 90 + 5x
=> 36 = 12x
=> x = 3
Therefore, Anuj in a day = 18 – 3 = 15 m