Directions: Read the following information to answer the question.
q = α–2 and pq = –α – 1
(p + q)2 = p2 + q2 + 2pq,
Thus (α–2)2 = p2 + q2 + 2(–α– 1)
p2 + q2 = α2 – 4α + 4 + 2α + 2
p2 + q2 = α2 – 2α + 6
p2 + q2 = α2 – 2α + 1 + 5
p2 + q2 = (α – 1)2 + 5
Thus, minimum value of p2 + q2 is 5.
Directions: Read the following information to answer the question.
X -> a = 300, d = 30, t = 10;
s = 5(600 + 9 × 30 × 12) = 870 × 5 × 12 = 52,200.
Y -> a = 200, d = 15, t = 20; s = 10(400 + 19 × 15) × 6 = 41,100.
Directions: Read the following information to answer the question.
If y = 2 (it cannot be 0 or 1), then x can take 1 value and z can take 2 values.
Thus with y = 2, a total of 1 X 2 = 2 numbers can be formed. With y = 3, 2 X 3 = 6 numbers can be formed. Similarly checking for all values of y from 2 to 9 and adding up we get the answer as 240.
Directions: Read the following information to answer the question.
Substitute possible figures in the given choices. In choice (a) x can be 2.9 and y can be – 6.9. In choice (c) this becomes 5(xy) which is less than x2y.