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Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2-7+2-8 = -11. Since -11 is divisible by 11, so is 2728.

Similarly, for 31415, the alternating sum of digits is 3-1+4-1+5 = 10. This is not divisible by 11, so neither is 31415. Coming to the given question, 7-M+4-2+8-7+6-M 16-2M So if M=8 then 16-16=0 so total number is divisible by 11

If a coin contains both heads then no way we get tail so probability is 0.

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9 of heart is single card hence prob = 1/52

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r=at2 s=2at therefore t=s/2a r=as^2/4a^2 s^2=4ar

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