

We know LCM*HCF=a*b
So a*b= 234*13
Factors of this product are 2*3*3*13*13
Hence smallest factor of product of two numbers is 2
log311 = 11*log3 = 11*0.4771 = 5.2481
Number of digits = Integral part of log + 1
Number of digits = 5+1 = 6
Distance in both the cases should remain constant. Using this,
5060*48 = 4060*speed
Speed = 60 km/h
If 10Cx=1, then what is the value of x if x≠0?
nCr = 1; if and only if r = 0 or n.
10Cx=1, x = 0 or 10.
Acc to ques.: x≠0, therefore. x = 10
To check the divisibility of 8 divide the last three digits by 8… putting the options D fits
better and the smallest one
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