

Speed in (km/hr) of first train=350/2=175
So speed of the second train=175*3/5=105
Possible values of x= 1,2,3,4……………….n
Except for x=1, y is always more than x to satisfy Equation : y=x2
log (a + b)/c + log c/a
B=4a=>log(5a) – log c + log c – log a
Log 5
take l.c.m of 7,18,36 and 56 gives 504
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2197 = 133 So log132197 = 3 log1313 = 3
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