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Q #6
:

Directions: Read the following information to answer the question.

A and B can do a work in 12 days, B and C in 15 days, C and A in 20 days. If A, B and C work together, they will complete the work in:

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Explanation :

 (A + B)'s 1 day's work =    1/12

 ; (B + C)'s 1 day's work =1/15

; (A + C)'s 1 day's work =    1/20

 Adding, we get: 2(A + B + C)’s 1 day’s work =1/12+1/15+1/20

=12/60=1/5

 (A + B + C)'s 1 day's work =1/10

 So, A, B and C together can complete the work in 10 days.


Q #7
:

Directions: Read the following information to answer the question.

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days. A lone can finish the remaining work?

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Explanation :

 B's 10 day's work =1/15 x 10 =2/3

 Remaining work =1 -2/3=1/3

 Now,1/18 work is done by A in 1 day.     

1/3 work is done by A in    18 x1/3

  = 6 days.


Q #8
:

Directions: Read the following information to answer the question.

A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work they can finish in a day?

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Explanation :

  A's 1 day's work =1/18

 and B's 1 day's work =1/9

(A + B)'s 1 day's work =1/18+1/9=1/6


Q #9
:

Directions: Read the following information to answer the question.

A, B and C can do a piece of work in 11 days, 20 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days?

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Explanation :

 (A + B)'s 1 day's work =    1/11+1/20

 =31/220

 (A + C)'s 1 day's work =    1/11+1/55=6/55

 Work done in 2 days =31/220+6/55

 =55/220=1/4

 Now,1/4

 work is done by A in 2 days.         

  Whole work will be done in (2 x 4) = 8 days.   


Q #10
:

Directions: Read the following information to answer the question.

A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

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Explanation :

 2(A + B + C)’s 1 day’s work =1/30+1/24+1/20

 =15/120=1/8

 (A + B + C)'s 1 day's work =1/16

 Work done by A, B and C in 10 days =10/16=5/8

. Remaining work =1 -5/8=3/8

 A's 1 day's work =1/16-1/24=1/48

 Now,1/48

 work is done by A in 1 day.             

 So,3/8  Work will be done by A in48 x3/8 = 18 days