Directions: Read the following information to answer the question.
Say SA, SB be the speed of A and B respectively. Since they are travelling for
the same time, therefore speed is directly proportional to distance.
SA/SB= 100/70 (by the time B has traveled 70 m A has traveled 100m)
To beat A by 20 m B will have to finish the race, by the time B will complete
380 m i.e., when A covers 280 m B will have to cover 330 m in the same time
so as to finish the race before A.
SA/SB’= 280/330, where SB’is the increased speed of B
SB’/SB = (33 × 10)/(28 × 7)
Now % increase will be {SB’/SA – 1} × 100 = {165/ 98 – 1} × 100 = 6.8%.
Directions: Read the following information to answer the question.
18:24 can be reduced to 3:4
As AB and BC are perpendicular, so on ratio scale, value of AC has to be 5.
3 × x + 4 × x + 5 × x = 48 ⇒ 12 × x = 48 ⇒ x = 4.
So, distance along AC is 5 × 4 = 20m.
Number of steps taken are = 20 × 6 = 120 steps.
Directions: Read the following information to answer the question.
30 kmph 20 kmph 10 kmph 40 kmph
A B C D E
250 m 250 m 250 m 250 m
Average AC = (2 × 30 × x)/(30 + x)
24 = 60x/(30 + x)
x = 20 kmph
Average AE = (Average AC & average CE)
19.2 = (2 × 24 × y)/(24 + y)
y = 16 kmph
Average CE = (2 × 40 × z)/(40 + z)
16 = 80z/(40 + z)
z = 10 kmph
Average BD = (2 × 20 × 10)/(20 + 10) = (400/30) = 13.33 kmph.
Directions: Read the following information to answer the question.
When Ajay has covered 52 m., Vijay has covered 48 m in the same time.
∴ Ratio of speeds = (Sa/Sv) = 52/48.
∴ To swim equal distances, the ratio of the time taken by each = (ta/tv) = 48/52.
Since ta = 67.2 sec., tv = 72.8 sec. = 1 min. 12.8 sec.