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Q #11
⏰ :

Directions: Read the following information to answer the question.

A thief, after committing a burglary, started fleeing at 12:00 noon, at a speed of 60 kmph. He was then chased by a policeman X. X started the chase 15 minutes after the thief had started, at a speed of 65 kmph. If another policeman had started the same chase along with X, but at a speed of 60 kmph, then how far behind was he when X caught the thief?

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The relative speed between the second policeman and X is 65 - 60 = 5 kmph. After 3 hours, the relative distance between them would be 15 km.

Q #12
⏰ :

Directions: Read the following information to answer the question.

In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hrs 18 min 15 seconds of watch time. What is the time gained or lost by this watch in one day?

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In a correctly running watch, the crossing of hands should take place exactly after every (720/11) = 65 5/11 minutes. In this watch, it takes place after [(3 hours, 18 minutes, 15 seconds)/3]  = (1 hour, 6 minutes, 5 second), i.e. 66 5/60 minutes of watch time. Thus the watch takes longer time to accomplish the task as compared to a correctly running watch. So this watch loses time = [(66 5/60) - (65 5/11)] = (83/132) minutes in 655/11 minutes of correct time. So in 1 day, i.e. (24 × 60) minutes of correct time, it will lose (83/6) minutes, i.e. 13 minutes 50 seconds.


Q #13
⏰ :

Directions: Read the following information to answer the question.

At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in six hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 mile round trip, the downstream 12 miles would then take only one hour less than the upstream 12 miles. What is the speed of the current in miles per hour?

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12/(x + a) + 6 =12/(x - a) ; and 12/(2x + a) + 1= 12/(2x - a)

Q #14
⏰ :

Directions: Read the following information to answer the question.

The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is

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Q #15
⏰ :

Directions: Read the following information to answer the question.

A gives B a start of 30m and beats him by 5 sec in a race of 300m . On another day he gives start A gives a start of 50m to B and still beats him by 1 sec. Find the velocity of B.(in m/s) (Assume both have been travelling at the constant speed through out)

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30 m + 5 sec is equivalent to 50m + 1 sec. Since it is to be covered by B.

Therefore , 50m – 30m = (5s -1s) VelocityB

VelocityB = 20m/4s = 5m/s