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Q #11
:

Directions: Read the following information to answer the question.

The integer 10133 and 12156 when divided by a three-digit integer n leave the same remainder. What is n?

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Solution :The required number will be the difference of the two given numbers or (a three digit) a factor of the difference 12156 – 10133 = 2023 2023 = 289 x 7 So The required three digit number = 289

Q #12
:

Directions: Read the following information to answer the question.

Find the least number which when divided by 5,6,7 leaves a remainder 3, but when divided by 9 leaves no remainder .

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Solution :L.C.M. of 5,6,7 = 210 => Required number is of the form 210k + 3 Least value of k for which (210k + 3) is divisible by 9 is k = 2. =>Required number = (210 X 2 + 3)= 423

Q #13
:

Directions: Read the following information to answer the question.

If a, b and c are odd natural numbers, which of the following is definitely true?

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Only a^b c is an odd natural number.

Q #14
:

Directions: Read the following information to answer the question.

62^3 – 54^3 – 8^3 is divisible by

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62^3 – (54^3 + 8^3)   

    62^3 – [(54 + 8) (54^2 + 8^2 – 54 x 8)]

    =62 x 3 x 54 x 8

    This is divisible both by 9 and 31


Q #15
:

Directions: Read the following information to answer the question.

What is the smallest number with which 200! should be multiplied to make it divisible by 12100?

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First find out how many 2`s and how many 3`s are available in 200! 200 when successively divided by 2 given 100, 50, 25, 12, 6, 3, 1, as the quotients and the sum of all these given the number of 2’s which is 197. 200 when successively divided by 3 gives 66 22,7,2as the quotion and the sum of all these gives the number of 3`s which is 97. For 12100 ., we have (2 2 x 3 )100 i.e. 2200 x 3100 we need 200 two`s and 100three `s where as we have 197 two`s and 97 3`s so, we need another three 2`s I.e. we need to multiply 200! by 23 x 3 3 = 8 x 27 = 216.