Directions : These questions are based on the data given below.
Directions : These questions are based on the data given below.
Solution. From 1 to 100, we have number like 3, 13, 23, 33 etc. which are 10 in number. Then number 30 to 39 have one 3 extra each giving 10 threes.
So, upto hundred, we have 10 + 10 = 20 threes. Since we have 700 pages we have number of 3’s as 7x20 = 140
Then all the 100 numbers from 300 to 399 have one 3 extra each giving a hundred 3’s So totally, 240 threes. Choice (1)
Directions : These questions are based on the data given below.
Solution.The number of toffees will be {(LCM of 4&5)k-1}i.e, 20k-1 since this is the number between 80 and 100, it can only be for k = 5 or 99 toffees.
If they are divided among 6 people, there will be three left.
Choice (3)
Directions : These questions are based on the data given below.
Solution. Statement I: Since a can take any value including those less than 25, this statement can be true.
Statement II: By observation, we can make out that 2a-b can be less than zero.
Statement III : 3a + 2b
=3(50-k) + 2 (25+l) = 200 – 3k + 2l
This can be grater than 200 since there is no restriction on the value if I where as k<50.
Choice (4)
I had some sweets (less than 80) with me. I distributed them among Sachin and Saurav. After distributing the sweets, it was found that both of them had got a different number of sweets, but both the numbers had the same unique properties. Both the numbers could be expressed as the sum of the squares of two different numbers and also as the difference of the cubes of two different numbers.
There are only three numbers less than 80, which satisfy both the conditions. They are :
26 = 52 + 12 = 33 – 13,
37 = 62 + 12 = 43 – 33 and
61 = 52 + 62 = 53 - 43
But, 61 + 26 > 80
...Saurav got 26 sweets
and Sachin got 37 sweets