Directions: Read the following information to answer the question.
Directions: Read the following information to answer the question.
Solution :From 1 to 100, we have number like 3, 13, 23, 33 etc. which are 10 in number. Then number 30 to 39 have one 3 extra each giving 10 threes.
So, upto hundred, we have 10 + 10 = 20 threes. Since we have 700 pages we have number of 3’s as 7x20 = 140
Then all the 100 numbers from 300 to 399 have one 3 extra each giving a hundred 3’s So totally, 240 threes.
Choice (1)
Directions: Read the following information to answer the question.
Solution :Only even prime number is 2 and only prime number ending with 5 is 5.
so Only 1 zero would be there in the end
Choice (2)
Directions: Read the following information to answer the question.
Solution: Let N and d be the number and divisor respectively then 3N when divided by d must leave a remainder of 3 x 11 = 33 but given remainder is 9.
⇒ 33 when divided by d leaves a remainder 9.
∴ d = 24 or 12
∴ required answer = remainder when 5 x 11 is divided by 24 or 12, which is 7 in either case.
Directions: Read the following information to answer the question.
Solution :N = 1365 x 289 x 2261, the remainder when N is divided by
19 = remainder of the product of the remainder of 1365, 289 and 2261. But since 2261 is divisible by 19, remainder = 0
Choice (1)