Mixture worth Rs 9.60

Oil 1=Rs 9.50         Rs  .10< mixture

Oil 2= Rs 10             Rs .40>mixture

L.C.M is  .40

Oil 1=4 , oil 2=1

Two varieties of oil are mixed in ratio 4:1

Listen ques first we can answer within 10 seconds

Given that,

3 parts of water

5 parts of syrup

Total parts is 8

Ques is mixture may be half water and half syrup

So, 4 parts of water  , 4 parts of syrup need

From 5 parts of syrup 1 part need to drawn and replace by water

So 1/5 part of mixture need to drawn and replace by water

1/5 part of syrup = 1 part

We don’t want to consider about 1/5 part of water , because again those filled by water only know.

Answer 1/5

Given that;

40 litres of mixture contains 10% water

Ques is 20% of water in the new mixture

10% of water in 40 liters is 4 liters

Now the 36 is 90% of  milk  in old mixture

In new mixture 20% of water, remaining 80% milk

36 litres milk= 80%

9(36/4) litres water =20%(80/4)

(36+9) 45 litres =(80%+20%)100%

5 liters water must be added to make 20% of water in the new mixture

Given that;

Mixture worth Rs 153 per kg

Tea 1=Rs 126 per kg         27<mixture     ratio=1

Tea 2=Rs 135 per kg        18<mixture       ratio=1

Tea 3=Rs ? per kg             ?>mixture        ratio=2

(27+18)45  < mixture ,this can tackle by 2 kg of Tea 3

It shares Rs 22.5 (45/2)per kg      

It must have Rs 22.5 per kg than the mixture rate (153 per kg)

The rate of the third tea is Rs 175.5(153+22.5) per kg

S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.

C.P. of 1 kg of the mixture = Rs.{100/110}x 68.20= Rs. 62