Directions: Refer the following data to answer the questions given below.
Milk in 1 litre mixture of A = 4/7 litre.
Milk in 1 litre mixture of B = 2/5 litre.
Milk in 1 litre mixture of C = 1/2 litre.
By rule of alligation we have required ratio X:Y
Directions: Refer the following data to answer the questions given below.
Spirit in 1 litre mix of A = 5/7 litre.
Spirit in 1 litre mix of B = 7/13 litre.
Spirit in 1 litre mix of C = 8/13 litre.
By rule of alligation we have required ratio X:Y
Directions: Refer the following data to answer the questions given below.
Let the rate of second quality be Rs x per Kg.
C.P of 1Kg wheat of 1st 980p
Step 1 :
S.P of 1 kg of mixture = Rs. 9.24
Gain = 10%
C.P of 1 kg of mixture =[100/100+10×9.24]=Rs.8.40
⇒Mean price = Rs. 8.40
Step 2 :
C.P of 1 kg of sugar of 1st kind = 900p
C.P of 1 kg of sugar of 2nd kind = 700p
Mean price = 840p
Directions: Refer the following data to answer the questions given below.
Let the rate of second quality be Rs x per Kg.
C.P of 1Kg wheat of 1st kind = 930p
C.P of 1 Kg wheat of 2nd kind = 100x p
Mean price = 1000p
By rule of alligation we have required ratio 8 : 7
Directions: Refer the following data to answer the questions given below.
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively.
When 9 litres of mixture are drawn off, quantity of A in mixture left:
7x–(7/12)×9=7x−21/4 litres
Similarly quantity of B in mixture left:
5x−(5/12)×9=5x−(15/4) litres
Therefore ratio becomes:
7x–(21/4)/5x−(15/4)+9=7/9
⇒(28x−21)/(20x+21)=7/9
⇒(252x−189)=140x+147
⇒112x=336
⇒ x=3
So the can contained: 7×x=7×3= 21 litres of A initially
