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Q #6
:

Directions: Refer the following data to answer the questions given below.

8 litres are drawn from a cask filled with wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the total solution is 16:81. How much wine did the cask hold originally?

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Let the quantity of the wine in the cask originally be x litres.

Using formula: 

Final Amount of solute that is not replaced= Initial Amount ×(Vol. after removal/Vol. after replacing)n

                                                                                       Or

Final ratio of solute not replaced to total = Initial ratio ×(Vol. after removal/Vol. after replacing)n

Then ratio of wine to total solution in cask after 4 operations:

1×(x−8/x)4=16/81

 (considering 2nd formula here)

(x−8)/x=2/3

  3x−24=2x

x=24 litres.


Q #7
:

Directions: Refer the following data to answer the questions given below.

A man travelled a distance of 90Km in 9 hours partly on foot at 8 kmph and partly on bicycle at 17 kmph. Find the distance travelled on foot.

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Distance covered in 1 hour on foot = 8 km 

Distance covered in 1 hour on bicycle = 17 km

Average distance covered in 1 hour = 90/9 km   = 10km (mean distance)


Q #8
:

Directions: Refer the following data to answer the questions given below.

A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

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Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water then quantity of water in new mixture

=3–3x/8+x litres

Quantity of syrup in new mixture =5−5x/8 litres

Therefore3−3x/8+x=5−5x/8

5x+24=40−5x

10x=16

x=8/5

So part of the mixture replaced = 

8/5×1/8=1/5


Q #9
:

Directions: Refer the following data to answer the questions given below.

A milk vendor has 2 cans of milk .The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the container so as to get 12 litres of milk such that the ratio of water to milk is 3:5?

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Milk in 1 litre mixture in 1st can = 3/4 litre. 

Milk in 1 litre mixture in 2nd can = 1/2 litre. 

Milk in 1 litre final mixture = 5/8 litre. 

By rule of alligation we have required ratio 5 : 8


Q #10
:

Directions: Refer the following data to answer the questions given below.

Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1:1:2. If the mixture is worth Rs 153 per Kg , the price of the third variety per Kg will be?

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Since first and second varieties are mixed in equal proportions.

So, their average price = Rs.(126+135/2)=Rs.130.50

So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x

 

By the rule of alligation, we have: