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Q #21
⏰ :

Directions: Read the following information to answer the question.

In a locality, two-thirds of the people have cable-TV, one-fifth have VCR, and one-tenth have both, what is the fraction of people having only cable TV ?

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Q #22
⏰ :

Directions: Read the following information to answer the question.

sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero?

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If we consider the third term to be ‘x”

The 15th term will be (x + 12d)

6th term will be (x + 3d)

11th term will be (x + 8d) and 13th term will be (x + 10d)

Thus, as per the given condition, 2x + 12d = 3x + 21d. 

Or x + 9d = 0 

x + 9d will be the 12th term.


Q #23
⏰ :

Directions: Read the following information to answer the question.

Every ten years the Indian government counts all the people living in the country. Suppose that the director of the census has reported the following data on two neighbouring villages Chota Hazri and Mota Hazri: Chota Hazri has 4,522 fewer males than Mota Hazri Mota Hazri has 4,020 more females than males. Chota Hazri has twice as many females as males. Chota Hazri has 2,910 fewer females than Mota Hazri. What is the total number of males in Chota Hazri?

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Q #24
⏰ :

Directions: Read the following information to answer the question.

Let x, y, z be three positive real numbers in a geometric progression such that x < y < z. If 5x, 16y, and 12z are in an arithmetic progression then the common ratio of the geometric progression is

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Since x, y ,and z are in G.P.  and x<y<z, let x = a, y=ar and z=ar2, where a>0 and r>1.

 

It is also given that, 15x, 16y and 12z are in A.P.

 

Therefore, 2×16y=5x+12z

 

Substituting the values of x, y and z we get,

 

32ar = 5a +12ar2

  • 32r = 5 +12r2

 

  • 12r 2 − 32r + 5 = 0

 

On solving the above quadratic equation we get r=1/6 or 5/2.

 

Since r>1, therefore r=5/2.


Q #25
⏰ :

Directions: Read the following information to answer the question.

If among 200 students, 105 like pizza and 134 like burger, then the number of students who like only burger can possibly be

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