Directions: Read the following information to answer the question.
We have g = x
d + e + f = 60
a + b + c=65
a + b + c + d + e + f + g + x = 145
65 + 60 + 2g = 145
2g = 20
g = 10
Directions: Read the following information to answer the question.
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The minimum possible strength of the class = 59 The maximum possible strength of the class = 17 x 4 = 68. The total number of friendships in the class is either 4b or 3g (where b is the number of boys and g is the number of girls) Hence = 4b = 3g ⇒g : b = 4 : 3. ⇒ The total number of students must be a multiple of 4 + 3 = 7 ∴ The only possible multiple of 7 which lies between the minimum possible strength of the class and the maximum possible strength of the class is 63. |
Directions: Read the following information to answer the question.
Directions: Read the following information to answer the question.
Directions: Read the following information to answer the question.
2x + 8 = 3x = 6x – 4 –2x – 8
8-x = 4x – 12
x = 4
Sum of 10 terms = 10 (2*12+9*4)/2 = 300