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TCS ION CCQT Quants Questions




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Q #11
:


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Quants Question

Directions: Refer the following data to answer the questions given below.

Milk and water are mixed in a vessel A in the ratio 5 : 3 and in vessel B in ratio 9 : 7 . In what ratio should quantities be taken from the two vessels so as to form a mixture in which milk and water will be in the proportion of 7 : 5 ?

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In vessel A, milk = 5 / 5 + 3 = 5 / 8 of the weight of mixture 

In vessel B milk = 9 / 9 + 7 = 9 / 16 of the weight of mixture

Now, we have to form a mixture in which milk be 7 / 12 of the weight of the mixture


Q #12
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Quants Question

Directions: Read the following information to answer the question.

A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

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Explanation :

 Suppose A, B and C take x,x/2andx/3

  hours respectively to finish the work.     

 Then,1/x+2/x+3/x=1/2

 6/x=1/2

 x = 12.         

 So, B takes 6 hours to finish the work.


Q #13
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Quants Question

Directions: Read the following information to answer the question.

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 dyas. How much is to be paid to C?

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Explanation :

 C’s 1 day’s work =1/3-1/6+1/8

=1/3-7/24=1/24

 A’s wages : B’s wages : C’s wages =1/6:1/8:1/24

 = 4 : 3 : 1.     

 C's share = Rs.1/8 x 3200 = Rs. 400


Q #14
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Quants Question

Directions: Read the following information to answer the question.

Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked1/3 as efficiently as he actually did, the work would have been completed in 3 days. A alone could complete the work in:

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Explanation :

 Let A’s 1 day’s work = x and B’s 1 day’s work = y.

 Then, x + y =1/5and 2x +1/3

 y =1/3

 Solving, we get : x =4/25

and y =    1/25

A's 1 day's work =4/25

 So, A alone could complete the work in    25/4days


Q #15
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Quants Question

Directions: Read the following information to answer the question.

Lee was riding his bike. After travelling the distance of 30 km, he sensed an unusual sound from the engine so he reduced his speed to 3/4th of the initial speed and reached the destination 45 min late. Had he sensed the sound 12 km farther, he could have made up 15 min. Find the total distance of the journey.

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To cover up 15 min, the distance travelled with normal speed = 12 km

∴To cover up 45 min, the distance to be travelled at normal speed = 36 km

Total distance travelled = 30 + 36 = 66 km.