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TCS ION CCQT Quants Questions




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Q #6
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Quants Question

Directions: Read the following information to answer the question.

If F(n) = {x/x is a prime factor of n}; answer the following questions. The least value of x when F(x)?F(15) = F(30)2

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F (15) = {3, 5}

    F (30) = {2, 3, 5}

    This least value of x would be 2

    Since F(2) ∪ F(15) = F(30)

 


Q #7
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Quants Question

Directions: Read the following information to answer the question.

Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had?

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Answer :23 Solution : books are between 15 and 30 if he gives to two of his friends then no. of books may be 17,19,21,23,25,27,29.again he give books to of his 3 friends then no. of books may be 17,23 and 29. Now he have to give books to of bhis 4 friends then no. of books will be 23. Hence proved.

Q #8
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Quants Question

Directions: Read the following information to answer the question.

What will be last digit of 22^45 ?

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Answer:2 Explanation: 22^45 we will take base 2 here .so we will use cyclicity of 2 here. 45/4 gives remainder 1 so 2^1=2. hence proved

Q #9
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Quants Question

Directions: Read the following information to answer the question.

Let x, y and z be distinct integers, x and y are odd and positive, and z is even and positive. Which one of the following statements can is true?

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(x – z) = odd – even = odd; y = odd. Odd × odd will always give odd, hence the first statement is wrong.

Q #10
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Quants Question

Directions: Refer the following data to answer the questions given below.

Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1:1:2. If the mixture is worth Rs 153 per Kg , the price of the third variety per Kg will be?

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Since first and second varieties are mixed in equal proportions.

So, their average price = Rs.(126+135/2)=Rs.130.50

So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x

 

By the rule of alligation, we have: