Where the code consists of only 1 digit. We could have 5 possible codes

Where the code consists of 2 digits. Since all the digits have to be keyed in at once there is no possibility of repetition. Both the digits have to be unique. So for the first digit we have 5 options and for the second we have 4 options. 5*4=20. However, we have considered the different orders as well which we need to convert back into the unordered combinations by dividing by 2!. 20/2=10 possible codes Where the code consists of 3 digits. Using the principles mentioned in statement 2 we have 5*4*3/3!=10 possible codes Where the code consists of 4 digits. We have 5*4*3*2/4!=5possible codes Where the code consists of 5 digits. We have 5*4*3*2*1/5!=1 possible codes Summing up we have 5+10+10+5+1=31

OR

5C1+5C2+5C3+5C4+5C5=5+10+10+5+1=31.

0.5x-40=250 so x=580 now 1/10th of 580 is 58

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Total number sample space two chocolates can be drawn in the way of n(S) = 15C2= 105 At least one to be nestle.. n(E) = 10C1 X5C1 + 10C2 X 5C0 = 95 P(E) = 95/105 = 19/21

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In one kg there are 5 heads of corn so one kg maize corns is 20 Rs. cost price of 1 head corn is 20/5 that is 4 Rs. selling price of 1 corn is 8 .. in one day we should get profit 200 Rs. let x be no. of maize corn should be sold to get 200 Rs as profit.. We know that profit =SP-CP.. So 8x-4x=200 then x=50

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(because A itself is a vowel).

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