Let breadth be x then length=4x

So area = 4x2 = 2500 => x = 25 and hence length = 4(25) = 100

Let atul sold it in Rs x Now that will be CP for irfan and hence

495000 = 90/100(x) => x= 550000

So profit % to atul = 100000/450000 * 100 = 22.22%

If marked price=x, cost price=CP . As 5x/7 is 115 of CP, so x will be x*115/(5x/7)of CP=161 of CP % Profit earned ,if sold at marked price=61

let total distance is x

x-(4/5x+3/20x)=1

x-[(16+3)/20]=1

1/20x=1

X=20Km

Let a=4.56, b=5.44

We know a3+b3=( a+b)(a2-ab+b2)

(4.56+5.44)(4.562-4.56*5.44+5.442)/ (4.562-4.56*5.44+5.442)

4.56+5.44

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