

Directions: Read the following information to answer the question.
We are given that AB = BC = CD = 12 km. ∴ time taken to travel AB at a speed of x kmph is (12/x) hours. This is followed by a break of x hours. His speed from C to D is 2(2x) = 4x kmph. Continuing on these lines, we get, [(12/x) + x + (12/2x) + 2x + (12/4x)] = 16 hours. Solving we get x = 3.
Directions: Read the following information to answer the question.
The maximum speed he can attain is 400/80 = 5m/s. The speed for first lap
is 400/100 = 4m/s. 5 > 4(1.1 )n–1 where n denotes the no. of laps. Maximum
value of n = 3.