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Q #11
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Quants Question

Directions: Refer the following data to answer the questions given below.

Tea worth Rs 126 per kg and Rs 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 153 per kg the price of the third variety per kg will be:

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Q #12
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Quants Question

Directions: Refer the following data to answer the questions given below.

In an apartment complex, the number of people aged 51 years and above is 30 and there are at most 39 people whose ages are below 51 years. The average age of all the people in the apartment complex is 38 years. What is the largest possible average age, in years, of the people whose ages are below 51 years?

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Let the average age of people aged 51 years and above be x years. Let the average age of people aged below 51 years be y years. Let the number of people aged below 51 years be N. Given, the average age of all the people in the apartment complex is 38 years. Therefore, x?30?y?N? 38 ….(1) 30?N We want to maximize y, which occurs when x is minimum i.e. for x=51. Substituting the value of x in (1) we get 390=N×(38-y) Again, when y is maximum, N is also maximum i.e. 39 Therefore maximum value of y = 28.

Q #13
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Quants Question

Directions: Read the following information to answer the question.

There are four varieties of pipes Pipe A, Pipe B, Pipe C and Pipe D. Each pipe can be either an inlet pipe or an outlet pipe but cannot be both. there are 5 tanks of equal volume.

Tank P is filled by Pipe A and Pipe B

Tank Q is filled by Pipe A and Pipe C

Tank R is filled by Pipe A and Pipe D

Tank S is filled by Pipe B and Pipe C

Tank T is filled by Pipe C and Pipe D

Time taken for the first 3 tanks (P, Q and R) to get filled are in the ratio 1:2:4 and the time taken for the S and T tanks to be filled are in the ratio 7:10.

Find the outlet pipes among the 4 varieties.

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Solution:

Let A,B,C and D do a,b,c and d with of work in an hour.

Let A and B fill the tank in 1 hour. 

Then A and C would fill the tank in 2 hours while A and D in 4 hours.

a+b=1 ---------- (i)

a+c=1/2 ----------- (ii)

a+d=1/4 ------------ (iii)

Let B and C take 7k hours while c and D take 10k hours to fill the tank

⇒ b+c=1/7k --------------- (iv)

 

c+d=1/10k -------------- (v)

 

a=[(i)+(ii)−(iv)]/2 = [(ii)+(iii)−(v)]/2

 

⇒ a={1+1/2−1/7k}/2={1/2+1/4−1/10k}/2 ---------- (vi)

⇒ k=4/70

On substituting value of k in equation (vi) we get a<0

⇒ a<0,b>0,c>0 and d>0

Hence only A is the outlet pipe.


Q #14
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Quants Question

Directions: Read the following information to answer the question.

A fill pipe can fill a tank in 20 hours, a drain pipe can drain a tank in 30 hours. If a system of n pipes (fill pipes and drain pipes put together) can fill the tank in exactly 5 hours, which of the following are possible values of n (More than one option could be correct)?

  1. 32
  2. 54
  3. 29
  4. 40


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3 fill pipes cancel out 2 drain pipes. Plus, you need an additional 4 fill pipes fill the tank in 5 hours. so the answer has to be 5k + 4. Both 54 and 29 are possible.

Q #15
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Quants Question

Directions: Read the following information to answer the question.

Pipe A, B and C are kept open and together fill a tank in t minutes. Pipe A is kept open throughout, pipe B is kept open for the first 10 minutes and then closed. Two minutes after pipe B is closed, pipe C is opened and is kept open till the tank is full. Each pipe fills an equal share of the tank. Furthermore, it is known that if pipe A and B are kept open continuously, the tank would be filled completely in t minutes. How long will it take C alone to fill the tank ?

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A is kept open for all t minutes and fills one-third the tank. Or, A should be able to fill the entire tank in '3t' minutes.
A and B together can fill the tank completely in t minutes. A alone can fill it in 3t minutes.
A and B together can fill 1/t of the tank in a minute. A alone can fill 1/3t of the tank in a minute. So, in a minute, B can fill 1/t 1/3t = 2/3t  

 Or, B takes 3t/2 minutes to fill an entire tank.
To fill one-third the tank, B will take t/2 minutes. B is kept open for t - 10 minutes.
t/2 = t - 10, t = 20 minutes.
A takes 60 minutes to fill the entire tank, B takes 30 minutes to fill the entire tank. A is kept open for all 20 minutes. B is kept open for 10 minutes.
C, which is kept open for 8 minutes also fills one-third the tank. Or, C alone can fill the tank in 24 minutes.