

Directions: Refer the following data to answer the questions given below.
S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.
C.P. of 1 kg of the mixture = Rs.{100/110}x 68.20= Rs. 62
Directions: Read the following information to answer the question.
Explanation :
A's 1 hour's work =1/4
; (B + C)'s 1 hour's work =1/3
; (A + C)'s 1 hour's work =1/2
(A + B + C)'s 1 hour's work =1/4+1/3
=7/12
(A + B + C)'s 1 hour's work =1/4+1/3=7/12
B's 1 hour's work =7/12-1/2 =1/12
B alone will take 12 hours to do the work.
Directions: Read the following information to answer the question.
Explanation :
Part of the work done by A ={1/10}x 5= 1/2
Part of the work done by B ={1/15}x 5=1/3
Part of the work done by C = 1 - 1/2+1/3=1/6
So, (A’s share) : (B’s share) : (C’s share) =1/2:1/3:1/6 = 3 : 2 : 1
A's share = Rs{.3/6}x 1500= Rs. 750, B's share = Rs.{2/6}x 1500 = Rs. 500.
C's share = Rs.{1/6}x 1500 = Rs. 250.
A’s daily wages = Rs.750/5
= Rs. 150, B's daily wages = Rs. 500/5 = Rs. 100.
C’s daily wages = Rs.250/2
= Rs. 125.
Daily wages of B and C = Rs. (100 + 125) = Rs. 225.
Directions: Read the following information to answer the question.
The time the distance between A & B will be 24m at two times when A has covered relative distance of 36m or 84m.
84/(17-13) = 21s
Directions: Read the following information to answer the question.
Let, speed of train = x km/hr
Relative speed while crossing 1st person = 5 ( x − 3) 18
Distance = length of train = 5 ( x − 3)× 9 ··· (I) 18
Relative speed while crossing 2nd person
= 5 ( x − 6) 18
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Distance = length of train = |
5 |
( x − 6)×10 |
···(II) |
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18 |
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From equation (I) & (II) we get |
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5 |
( x − 3)× 9 = |
5 |
( x − 6)×10 |
or 9x – 27 = 10x – 60 |
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18 |
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18 |
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x = 33 km/hr