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Capgemini Quants Questions




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Q #6
:


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Quants Question

Directions: Read the following information to answer the question.

If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to:

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Since 653xy is divisible by 2 as well as by 5, so y = 0 Now 653x0 is divisible by 8 so 3x0 is also divisible by 8. By hit and trial x=6 and x+y = 6

Q #7
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Quants Question

Directions: Read the following information to answer the question.

Summish wants to pack 108 oranges, 180 apples and 240 pears in boxes. His friend Arun lays down a condition that a box should have only one kind of fruit and the number of fruits in all boxes should be the same and number of boxes should also be minimum. How many boxes will Summish need to pack all the fruits?

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Answer:44 Explanation: HCF of 108,180,240 is 12. Now for oranges required boxes =108/12=9 Similarly for apple=180/12=15 For pears 240/12=20 Total boxes required 9+15+20=44 Hence proved.

Q #8
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Quants Question

Directions: Read the following information to answer the question.

What is the remainder of (327 + 422 + 955) ÷ 9 ?

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Answer:3 Explanation:327/9 gives 3 remainder 422/9 gives 8 remainder and 955/9 gives 1 as a remainder.adding all 3 remainders wer Have 12 whwn divided by 9 it gives 3. Hence proved.

Q #9
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Quants Question

Directions: Refer the following data to answer the questions given below.

8 litres are drawn from a cask filled with wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the total solution is 16:81. How much wine did the cask hold originally?

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Let the quantity of the wine in the cask originally be x litres.

Using formula: 

Final Amount of solute that is not replaced= Initial Amount ×(Vol. after removal/Vol. after replacing)n

                                                                                       Or

Final ratio of solute not replaced to total = Initial ratio ×(Vol. after removal/Vol. after replacing)n

Then ratio of wine to total solution in cask after 4 operations:

1×(x−8/x)4=16/81

 (considering 2nd formula here)

(x−8)/x=2/3

  3x−24=2x

x=24 litres.


Q #10
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Quants Question

Directions: Refer the following data to answer the questions given below.

In what proportion must wheat at Price 4.10 per kg must be mixed with wheat at Price 4.60 per kg, so that the mixture be worth Rs 4.30 a Kg ?

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Here, CP of unit quantity of Dearer = 460 per kg , 

CP of unit quantity of Cheaper = 410 per kg 

So we can use above formulas : 

Quantity of cheaper/Quantity of dearer =

{C.P of dearer-Mean price}/{Mean price-C.P of cheaper}

460-430/430-410=30/20=3/2