Directions: Read the following information to answer the question.
Solution:
C’s one day’s work =(1/3)−(1/6+1/8)=1/24
Therefore, A:B:C = Ratio of their one day’s work =1/6:18:1/24
=4:3:1
A’s share =Rs.600×(4/8)=300
B’s share =Rs.600×(3/8)=225
C’s share =Rs[600−(300+225)]= Rs 75
Directions: Read the following information to answer the question.
Solution:
Let there be 'n' fill pipes attached to the tank.
Therefore, there will be 12–n drain pipes attached to the tank
Each fill pipe fills the tank in 8 hours. Therefore, each of the fill pipes will fill (1/8)th of the tank in an hour.
Hence, n fill pipes will fill n×1/8=n/8 of the tank in an hour.
Each drain pipe will drain the tank in 6 hours. Therefore, each of the drain pipes will drain (1/6)th of the tank in an hour.
Hence, (12−n) drain pipes will drain (12−n)×1/6=12−n/6
of the tank in an hour.
When all these 12 pipes are kept open, it takes 24 hours for an empty tank to overflow. Therefore, in an hour (1/24)th of the tank gets filled.
Hence, n/8–12−n/6=1/24
i.e.
{3n–4(12−n)}/24=1/24
⇒ 7n−48=1
⇒ 7n=49 or n= 7
Directions: Read the following information to answer the question.
Solution:
From the given information Q is thrice as efficient as P.
R is thrice as efficient as Q.
S is thrice efficient as R.
If work done by P in a day is 'n' units, the work done in a day by Q, R and S would be 3n, 9n and 27n units respectively.
It can be seem that, P,Q and R working together can do 13n units in a day while P,Q and S working together can do 31n units in a day.
Hence, the ratio of times taken to complete the work by the former and later groups is 31:13
P,Q and S take 13 days.
Directions: Read the following information to answer the question.
Solution:
Pipe A fills the tank at the rate of 40 litres a minute. Pipe B at the rate of 30 litres a minute and Pipe C drains the tank at the rate of 20 litres a minute.
If each of them is kept open for a minute in the order A-B-C, the tank will have 50 litres of water at the end of 3 minutes.
After 13 such cycles, the tank will have 13×50=650 litres of water.
It will take 13×3=39 minutes for the 13 cycles to be over.
At the end of the 39th minute, Pipe C will be closed and Pipe A will be opened. It will add 40 litres to the tank.
Therefore, at the end of the 40th minute, the tank will have 650+40=690 litres of water.
At the end of the 40th minute, Pipe A will be closed and Pipe B will be opened. It will add 30 litres of water in a minute.
Therefore, at the end of the 41th minute, the tank will have 690+30=720 litres of water.
But then at 700 litres, the tank will overflow. Therefore, Pipe B need not be kept open for a full minute at the end of 40 minutes.
Pipe B needs to add 10 more litres of water at the end of 40 minutes. It will take (1/3)rd of a minute to fill 10 litres of water.
Therefore, the total time taken for the tank to overflow=40 minutes +1/3 of a minute
or 40 minutes 20 seconds.
Directions: Read the following information to answer the question.
Solution:
Let the total distance to be covered be d
On each day under normal weather conditions they travel d/20
of the distance.
On 1st day they would travel =d/20
On 2nd day they would travel =0.8×d/20
On 3rd day they would travel =0.8×(0.8×d/20)
Let he will reach the point B in nth day
⇒ d/20+0.8 *d/20+0.82*d/20+…….+0.8n*d/20=d
⇒ d/20×(−(0.8)n+1)/(−0.8+1)=d
⇒ 1−(0.8)n=4(0.8)n=−3
Since (0.8)n>0, thus it is never equal to -3
The man will never reach the point B.