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Q #16
:

Directions: Read the following information to answer the question.

Two persons start, one from point A towards B and the other from B towards A. Distance between A and B is d meters. The person starting from B gives a whistle as soon as he starts and the person starting from A hears the whistle after 10 seconds of his (A) start. Speed of A and B are 2m/s and 1.5m/s respectively. Speed of sound is 330m/s.

After hearing the whistle from person B, immediately person A gives a whistle which the person B will listen after how many seconds?

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Now if the person B has to hear the whistle from A, Both of them i.e., the

person B and the sound of the whistle from A will have to travel the distance

of 3320 – 20 – 15 = 3285 m. Relative speed will be Ss + Sb = 330 + 1.5 =

331.5 m/s. So the time taken will be 9.9  second.


Q #17
:

Directions: Read the following information to answer the question.

There are three major cities in Maharashtra Mumbai, Pune and Nagpur which form the vertices of a triangle. A trader in any city will trade to that city which is close to his city as per linear distance. Shortest distance between Pune and Nagpur is 350 km. The measure of angle between line joining Mumbai and Pune and Mumbai and Nagpur is 45°. The measure of angle between line joining Mumbai and Pune and Pune and Nagpur is 60°.

Which city does the trader from Mumbai should trade and what is the shortest distance between Mumbai and city he trades?

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M, P & N be the points representing Mumbai, Pune & Nagpur respectively.

Angle m, p & n are 45°, 60° & 75° respectively. Trader from Mumbai will

trade to that city which is near to it. From triangle MPN it is clear that Nagpur

is near to Mumbai as side opposite to greater angle is greater in a triangle.

To find distance of Mumbai from Nagpur apply Sine rule in Triangle MPN.

. By solving MN ≈ 428 km.


Q #18
:

Directions: Read the following information to answer the question.

There are three major cities in Maharashtra Mumbai, Pune and Nagpur which form the vertices of a triangle. A trader in any city will trade to that city which is close to his city as per linear distance. Shortest distance between Pune and Nagpur is 350 km. The measure of angle between line joining Mumbai and Pune and Mumbai and Nagpur is 45°. The measure of angle between line joining Mumbai and Pune and Pune and Nagpur is 60°.

What is the Minimum cost of transport for trade from Mumbai if transport cost = Rs.3/km?

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A trader from Mumbai will have minimum cost of transport if trades with city

which close to Mumbai. Thus he should trade with Nagpur for Minimum

Transport cost. Thus minimum Transport cost = 425 × 3 = 1300.


Q #19
:

Directions: Read the following information to answer the question.

There are three major cities in Maharashtra Mumbai, Pune and Nagpur which form the vertices of a triangle. A trader in any city will trade to that city which is close to his city as per linear distance. Shortest distance between Pune and Nagpur is 350 km. The measure of angle between line joining Mumbai and Pune and Mumbai and Nagpur is 45°. The measure of angle between line joining Mumbai and Pune and Pune and Nagpur is 60°.

If trader from Mumbai has to trade with both the cities what is the minimum transport cost? A trader can follow a sequential trade to minimize cost instead of direct transport. Sequential trade means trade to city C from City A can be done via city B after trading with B and trade is continued from B to (C) However direct trade can also be followed. Transport cost = Rs.2/km.

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A trader from Mumbai will have minimum transportation cost if he travels by

shortest route for entire journey. Thus instead of travelling to both the cities

directly if he follows sequential trade in this problem he travels by shortest

route. Thus he should go to Pune via Nagpur. He travels distance of 775km.

Therefore transportation cost = 775 × 2 = 1550.


Q #20
:

Directions: Read the following information to answer the question.

A man can walk up a moving ‘up’ escalator in1/2 minutes. He can walk down this moving ‘up’ escalator in 1.5 minutes. His walking pace is the same up stairs as it is down stairs.

How long would it take him to climb the escalator stairs if it was not moving?

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In 1.5 minutes the man can walk down 1 moving escalator or up 3. In 3

minutes walking, half the time up and half the time down, he can walk 4

escalator lengths. This is his walking pace – 4 escalator lengths in 3 minutes

– for the effect of the moving escalator is canceled. He can therefore climb

(or descend) the still escalator in 1/4 of 3 minutes, or 45 seconds. In the 1.5

minutes required to walk down the moving “up” escalator he walks the

equivalent of 2 still escalators. Therefore the escalator must have moved

up once in that lime and its speed is 1 length In 1.5 minutes.

Aliter : If x = number of steps, e = speed of escalator and m = speed of man,

we get e + m = x/30; –e + m = x/90. On adding these equations, we get

m = x/45 and e comes to x/90. We can now solve for required values.

33.