Directions: Refer the following data to answer the questions given below.
Directions: Refer the following data to answer the questions given below.
Directions: Read the following information to answer the question.
Solution:
Pipe A fills the tank at the rate of 40 litres a minute. Pipe B at the rate of 30 litres a minute and Pipe C drains the tank at the rate of 20 litres a minute.
If each of them is kept open for a minute in the order A-B-C, the tank will have 50 litres of water at the end of 3 minutes.
After 13 such cycles, the tank will have 13×50=650 litres of water.
It will take 13×3=39 minutes for the 13 cycles to be over.
At the end of the 39th minute, Pipe C will be closed and Pipe A will be opened. It will add 40 litres to the tank.
Therefore, at the end of the 40th minute, the tank will have 650+40=690 litres of water.
At the end of the 40th minute, Pipe A will be closed and Pipe B will be opened. It will add 30 litres of water in a minute.
Therefore, at the end of the 41th minute, the tank will have 690+30=720 litres of water.
But then at 700 litres, the tank will overflow. Therefore, Pipe B need not be kept open for a full minute at the end of 40 minutes.
Pipe B needs to add 10 more litres of water at the end of 40 minutes. It will take (1/3)rd of a minute to fill 10 litres of water.
Therefore, the total time taken for the tank to overflow=40 minutes +1/3 of a minute
or 40 minutes 20 seconds.
Directions: Read the following information to answer the question.
Solution:
Let the number of days required by yana to finish the work alone be x days of 8 hrs.
Let the number of days required by urvashi to finish the work alone be y days of 8 hrs.
Let the number of days of overtime by yana and urvashi be p and k respectively.
So,in 12 days yana finishes 12/x+k/2x of work.
In 12 days,urvashi finishes, 12/y+p/2y of work.
So by condition 1, 12/x+12/y+k/2x+p/2y=1....(1)
By condition 2, 15/x+15/y+p/2y=1.....(2)
And,by condition 3, 20/x+20/y+k/2x=1.....(3)
Adding 2 and 3 and subtracting 1 from the result,
1/x+1/y=1/23.
So,if both work normally,they take 23 days.
Directions: Read the following information to answer the question.
Let the work done by Ahmed be 60 (LCM of 2,3,4,5)
So, work done per hour by:
Ahmed – 60/2 = 30
Bibhor – 60/3 = 20
Bibhor in 4 hours – 20 x 4 = 80
Deepak – 80/5 = 16
Therefore, total work done in an hour = 30 + 20 + 16 = 66
If all 3 work for 20 hours, total work done = 66 * 20
If Bibhor alone has to work, time taken to do 66 * 20 of work = 66 * 20/20 (work done by Bibhor in 1 hour)
= 66 hours