Directions: In each question, you are given certain data followed by two statements. For answering the questions:
A tractor travelled a distance of 5 m. What is the radius of the rear wheel?
Explanation: To find the radius of the rear wheel, we need to know the numerical value of its circumference. From statement (I), we get a relation between the circumferences of the two wheels in terms of “N”. From statement (II), we get similar information in terms of “t”. Thus, the radius cannot be determined from the given data and the answer is (1).
Directions: In each question, you are given certain data followed by two statements. For answering the questions:
How many different triangles can be formed?
Explanation: Although it is known that none of the lines are parallel to each other, there might be the case wherein all the lines have exactly one point of intersection, or eight lines with one point and the other eight with another point of intersection. Unless something about the relative arrangement of these lines is known, one cannot arrive at a definite answer. So the answer is (1).
Directions: Each question is followed by two statements. You have to decide whether the information provided the statements is sufficient for answering the question.
What is the area of the rectangle ABCD?
Explanation:From statement B, as the diagonals measure the same and the two adjacent sides are equal (from statement A) the figure is a square of side 10 cm. So the area of the figure can be determined.
Directions: Each question is followed by two statements. You have to decide whether the information provided the statements is sufficient for answering the question.
At what speed (in number of revolutions per minute) is fan A rotating?
Explanation: The radius of the fan may or may not have anything to do with speed of the fan.
Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
OAT+OAT+OAT = BOOT. As T=0, no carry for A+A+A(3A). Possible values of A and O can be calculated by
1) 3A= O
2) 3A = 10 +O
3) 3A = 20 + O
Here Largest carry generated by addition of three one digit number is 27(9+9+9).
Hence value of O is less than 7 for equation 3.
For Equation 3)
Assume value of O is 7. Therefore value of A=9
now carry + O + O + O = BO.
(2) + (7) + (7) + (7) = 23.
but 7 is not equal to 3. Contradict to our assumption.
Try another value of O as 4 for equation 3
O=4 therefore, A = 8.
now carry + O + O + O = BO.
(2) + (4) + (4) + (4) = 14.
hence value satisfied with our prediction. hence O=4 A=8 and B=1
now TOO + TOO = TAA