3651 has to be divisible by 3 and 7. For divisibility by 3, sum of digits must be divisible by 3. Therefore 3 must be added to 3651 to make it divisible by 3.
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A = k*B*?3 ; putting the values we get k=5. Now putting B=6, C=3 & k=5. Then A = 810.
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4 women wants to sit together out of 7 members so it can be done in 4! Ways. Now 4 women can be arranged in 4! Ways. So, 4!*4! Is the answer.
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A developer completes 6 ques in an hour.
So in 20 hours, he will complete (6*20 = ) 120 question.
Total questions to be done = 2400.
Required number of developers = 2400120 = 20.
From the reciprocals of HCF and LCM, we can find the HCF and LCM. HCF = 12 and LCM = 312.
Also we know that the product of HCF and LCM of two numbers is equal to the product of two numbers.
HCF x LCM = First number x second number
12 x 312 = 24 x second number
Second number = 156.