Let principal be P.
Acc to ques.: P∗4∗13100∗12 – P∗6∗8100∗12 = 40
P(521200 - 481200) = 40
P = Rs. 12000.
for calculating the compound interest at 15% apply 15+15+15*15/100 for two years equal to 32.25 I.e. 2.25% extra from 30% of simple interest 2.25%of 20000=450
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MP=400
D%=10
So, SP=400*90/100=360
P%=12
CP=360*100/(100+12)=300
LCM = 2970; HCF = 30
Factors of LCM = 2x3x3x3x5x11 and of HCF = 2x3x5
Product of two numbers = Product of LCM and HCF of the numbers
= 2x3x3x3x5x11x2x3x5
If a = 2 and b2 – ab = - 1 then what is the value of log(a+b)(a3 + b3)?
a = 2; b2 – ab = - 1
b2 – 2b + 1 = 0 (given a = 2)
(b - 1)2 = 0
b = 1
log(a+b)(a3+b3) = ?
Put values: log(1+2)(13+23) = log3(1+8) = log3(9) = log3(32) = 2log3(3) = 2
Alternatively;
a3+b3 = (a+b)(a2+b2-ab)
log(a+b)(a+b)(a2+b2-ab) = log(a+b)(a+b) + log(a+b)(a2+b2-ab)
= 1 + log(3)(4 - 1) = 1 + 1 = 2