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Q #6
:

IBPS Quants Question

Simple interest on an account at 4% per annum for 13 months is more than the simple interest on the same sum for 8 months at 6% per annum by Rs.40. What is the principal amount?
+

Let principal be P.

Acc to ques.: P41310012 P6810012 = 40

P(521200 - 481200) = 40

P = Rs. 12000.


Q #7
:

IBPS Quants Question

Swapna has kept Rs 2000 at 15% simple interest in bank for 2 years. If she kept the same amount at compound interest for 2 years. How much extra would she have earned?
+

for calculating the compound interest at 15% apply 15+15+15*15/100 for two years equal to 32.25 I.e. 2.25% extra from 30% of simple interest 2.25%of 20000=450

Q #8
:

IBPS Quants Question

The printed price on a book is Rs. 400 a bookseller offers a 10% discount on it. If he still earns a profit of 12 %, then the cost price of the book is:
+

MP=400

D%=10

So, SP=400*90/100=360

P%=12

CP=360*100/(100+12)=300


Q #9
:

IBPS Quants Question

The LCM and HCF of two numbers are 2970 and 30 respectively. Prime factors of the product of two numbers are:
+

LCM = 2970; HCF = 30

Factors of LCM = 2x3x3x3x5x11 and of HCF = 2x3x5

Product of two numbers = Product of LCM and HCF of the numbers

= 2x3x3x3x5x11x2x3x5


Q #10
:

IBPS Quants Question

If a = 2 and b2 – ab = - 1 then what is the value of log(a+b)(a3 + b3)?


+

a = 2; b2 – ab = - 1

b2 – 2b + 1 = 0 (given a = 2)

(b - 1)2 = 0

b = 1

log(a+b)(a3+b3) = ?

Put values: log(1+2)(13+23) = log3(1+8) = log3(9) = log3(32) = 2log3(3) = 2

Alternatively;

a3+b3 = (a+b)(a2+b2-ab)

log(a+b)(a+b)(a2+b2-ab) = log(a+b)(a+b) + log(a+b)(a2+b2-ab)

= 1 + log(3)(4 - 1) = 1 + 1 = 2