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Q #6
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Quants Question

Directions: Read the following information to answer the question.

If one-seventh of a number exceeds its eleventh part by 100 then the number is…

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Let the number be x. Then X/7 - x/11 =100 11x-7x = 7700 x=1925.

Q #7
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Quants Question

Directions: Read the following information to answer the question.

What is the highest number that will divide 87 and 122, leaving a remainder of 3 in each case?

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Answer:7 Explanation: 87-3=84 122-3=119. Hcf of 84 and 119 is 7. Hence proved.

Q #8
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Quants Question

Directions: Read the following information to answer the question.

What is the last digit of 5^2879 x 4^8945 x 2^127 x 7^249?

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Answer:0 Solution:unit digits are 5,4,8,7 respectively So onsolving we will get 0 as unit digit.

Q #9
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Quants Question

Directions: Refer the following data to answer the questions given below.

The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

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Milk in 1 litre mixture of A = 4/7 litre.
Milk in 1 litre mixture of B = 2/5 litre.
Milk in 1 litre mixture of C = 1/2 litre.


By rule of alligation we have required ratio X:Y

Q #10
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Quants Question

Directions: Refer the following data to answer the questions given below.

In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?

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SOLUTION S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%. C.P. of 1 kg of the mixture = Rs.{100/110}x 68.20= Rs. 62 BY the rule of alligation, we have : Cost of 1 kg tea of 1st kind Cost of 1 kg tea of 2nd kind Rs. 60 Rs. 65 Mean Price Rs. 62 3 2 Required ratio = 3 : 2.