Explanation: W O R L D + T R A D E --------------------- C E N T E R Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve. How? Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1). In the first right column, there is only one alphabet C and possible carry is 1. So, its vale should be 1. Now, from where this carry will come ?It will come from W+T.. Now, if we look towards left end, E and D can not be zero, otherwise the value of R would be same as either D or E. So, E can not be 1 or 0. So, consider it as 2 and solve rest. We can also take value of D as 3. But, E is coming many times in the question so we are taking E. We can take value of D as 3 as 3 is available. But, then value of L should be 9 and tge remaining numbers left would be 0,4,6,8,7. Which wont solve the question. So, we will take D=4 and see the remaining numbers. After trying hit and try method, we get the values as: C=1, W=5, T=7, O=3, R=6, E=2, A=0, N=9, D=4, L=8.