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Q #11
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Quants Question

Directions: Read the following information to answer the question.

A red light flashes 3 times per minute and a green light flashes 5 times in two minutes at regular intervals. If both lights start flashing at the same time, how many times do they flash together in each hour?

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Solution:

Red light flashes every 20 seconds

Green light flashes every 24 seconds

Therefore, they will flash together every 120 seconds

In every hour they will flash 3600/120= 30 times


Q #12
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Quants Question

Directions: Read the following information to answer the question.

Abhay, Ajay and Vijay wish to travel from town A to town B. They have one motorcycle which can be driven by any of them but can carry only two persons at a time. The distance between the two towns is 105 km and the speed at which they can walk is 5 kmph.

If the speed of the motorcycle is 20 kmph then what is the shortest possible time in which all three of them can complete the journey?

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Q #13
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Quants Question

Directions: Read the following information to answer the question.

Walking at his usual speed, a man can cover a distance of 96 km in a certain time. But he actually walks at an increased speed and every hour covers a distance which is 1 km more than he would have covered in 1.25 hours walking at his usual speed. Thus, he reaches the destination 2 hours sooner. What is the ratio of his usual time to his new time to cover the distance?

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Let the usual speed of the man be x km/hr.

So, walking at the usual speed, in 1.25 hrs. he can cover 5/4 x km i.e, walking

at increased speed, he would cover (5x/4 + 1) km/hr. Now, usual time – new

time = 2, 96/x – 96/(5x/4 + 1) = 2

Solving the above equation we get, x = 12.

i.e. his usual speed = 12km/hr and his

increased speed = 16km/hr So, his usual

time = 8 hours and his new time = 6

hours

So, ratio of times = 8 : 6 = 4 : 3.


Q #14
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Quants Question

How many 5 digit numbers can be made using 1, 2, 3, 4, 5 such that the digit in the unit place is greater than the digit in the hundred’s place?

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We can not have 1 at the unit’s place since it is the smallest number.

Number of ways ‘2’ at unit’s place..... hundred’s place can be filled in one way and remaining three places

in 1 × 2 × 3 = 6 ways.

Total number of ways in which 2 is at unit’s place is 6 × 1 = 6 ways.

Number of ways ‘3’ at unit’s place..... hundred’s place can be filled in two ways and remaining three places

in 1 × 2 × 3 = 6 ways.

Total number of ways in which 3 is at unit’s place is 6 × 2 = 12 ways.

Number of ways ‘4’ at unit’s place..... hundred’s place can be filled in three ways and remaining three

places in 1 × 2 × 3 = 6 ways.

Total number of ways in which 4 is at unit’s place is 6 × 3 = 18 ways.

Number of ways ‘5’ at unit’s place..... hundred’s place can be filled in four ways and remaining three places

in 1 × 2 × 3 = 6 ways.

Total number of ways in which 5 is at unit’s place is 6 × 4 = 24 ways.

So the total number of ways = 6 + 12 + 18 + 24 = 60.


Q #15
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Quants Question

What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8distinct girlfriends such that each of them gets at least one gift?

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