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CTET Logical Questions




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Q #21
:


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Logical Question

Directions: Read the following information to answer the question.

A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?

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Explanation :

 B's 1 day's work =1/12-    1/20

=2/60=1/30

 Now, (A + B)'s 1 day's work =1/20+1/60

 =4/60=    1/15

.    [  B works for half day only    ]         

 So, A and B together will complete the work in 15 days.


Q #22
:


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Logical Question

Directions: Read the following information to answer the question.

A, B and C can do a piece of work in 11 days, 20 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by B and C on alternate days?

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Explanation :

 (A + B)'s 1 day's work =    1/11+1/20

 =31/220

 (A + C)'s 1 day's work =    1/11+1/55=6/55

 Work done in 2 days =31/220+6/55

 =55/220=1/4

 Now,1/4

 work is done by A in 2 days.         

  Whole work will be done in (2 x 4) = 8 days.   


Q #23
:


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Logical Question

Directions: Read the following information to answer the question.

A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it?

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Explanation :

 Suppose B takes x days to do the work.

  A takes {2 x3/4}x=3x/2

 days to do it.         

 (A + B)'s 1 day's work =    1/18

 1/x=2/3x=1/18

 or x = 30


Q #24
:


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Logical Question

Directions: Read the following information to answer the question.

A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in:

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Explanation :

 (A + B + C)'s 1 day's work =1/24+1/6+1/12=7/24

 So, A, B and C together will complete the job in    24/7days.


Q #25
:


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Logical Question

Directions: Read the following information to answer the question.

A and B can do a piece of work in 72 days; B and C can do it in 120 days; A and C can do it in 90 days. In what time can A alone do it?

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Explanation :

 (A + B)'s 1 day's work =    1/72

 (B + C)'s 1 day's work =    1/120

 ; (A + C)'s 1 day's work =1/90

 Adding, we get: 2(A + B + C)’s 1 day’s work =1/72+1/120+1/90=12/360=1/30

 (A + B + C)'s 1 day's work =1/60

 So, A’s 1 day’s work =1/60-1/120 =1/120

  A alone can do that work in 120 days.