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Q #11
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Quants Question

Directions: Read the following information to answer the question.

Pipes A and B can fill a tank in 12 min and 16 min respectively. Both are kept open for 'n' min and then B is closed and A fills the rest of the tank in 5 min. The time 'n' after which B was closed is:

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Solution:

n(1/12+1/16)=28n/192

⇒ Left capacity =1–28n/192

This is filled by A in 5 min and fills 1/12 in 1 min

⇒ (192−28x)/192=5/12

⇒ n= 4 min


Q #12
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Quants Question

Directions: Read the following information to answer the question.

Pankaj can produce one unit in 15 days, while Bharti can do the same in 12 days. After producing one unit, working together, they received Rs. 90, which they distributed amongst themselves in proportional to their efficiency. If they work for 20 days, and sell the produce, then Bharti should receive

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Solution:

In 1 day Pankaj and Bharti together produce =1/15+1/12=3/20 units

In 20 days, together they can produce (3/20)20=3 units.

From which they can fetch Rs 270

Efficiency of Bharti/Efficiency of pankaj=15/12=5/4

⇒ Share of Bharti is (5/9)270= Rs 150


Q #13
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Quants Question

Directions: Read the following information to answer the question.

A gives B a start of 30m and beats him by 5 sec in a race of 300m . On another day he gives start A gives a start of 50m to B and still beats him by 1 sec. Find the velocity of B.(in m/s) (Assume both have been travelling at the constant speed through out)

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30 m + 5 sec is equivalent to 50m + 1 sec. Since it is to be covered by B.

Therefore , 50m – 30m = (5s -1s) VelocityB

VelocityB = 20m/4s = 5m/s


Q #14
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Quants Question

If a fair coin is tossed twice, what is the probability that on the first toss the coin lands heads and on the second toss the coin lands tails?
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Suppose first toss is A, second is B. We know that p(A_heads) = 50% and that p(B_tails) = 50%. Also, A and B are independent. So, p(A_heads and B_tails) = p(A_heads) * p(B_tails) = 50% * 50% = 25% = 1/4. Answer is C.

Q #15
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Quants Question

Ten different letters of English alphabet are given. Words with five letters are formed from these given letters. Then the number of words which have at least one letter repeated is

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Total number of 5 lettered words that can be formed using 10 letters, with repetition = 105

total number of 5 lettered words that can be formed using 10 letters, such that the all letter used are

distinct = 10 × 9 × 8 × 7 × 6 = 30240.

Total words that have atleast one letter repeated

= 105 – 30240

= 69760.