Multiplying a number with any natural number will not give HCF.

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Permutation on Keeping two S together and subtracting from the total permutation of “passenger”. Total permutation= 9!/2!*2!; two S together the permutation is 8!/2!. on subtracting (8!*7)/4

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For making a four digit number we have to fit a multiple of 2 in the last place_ _ _ _

Last place can be filled by 3 ways

No of ways when 2 is in last place = 18

No of ways when 4 in last place = 18

No of ways when 0 is in last place =24

Total no of ways = 60.

6-digit number is formed from 214635, even numbers are 2, 4, 6

Last digit is filled by 2,4,6 hence 3 ways to fill

Second last digit is filled by 5 ways, repetition is not allowed.

Third last digit is filled by 4 ways

Third digit is filled by 3 ways

Second digit is filled by 2 ways

First digit is filled by 1 way. Therefore no of ways= 3*5*4*3*2*1= 360

Girls=6, Boys=8

P( exactly 3 boys in group of 6)= (8C3 * 6C3) / 14C6