Directions: Read the following information to answer the question.
At the given time the angle between the hands of the clock = 284°.
The time required to change this angle to be reduced to 0° =
284
5.5 min.
= 51.6 min.
∴ The angular displacement of min hand = 51.6 × 6° = 309.6°.
(The min-hand covers 6° in 1 min.)
Directions: Read the following information to answer the question.
Relative angular displacements between two hands of clock in 1 min. is
5.5° / min.
∴ After 13 min. angle will be 210 – 5.5 × 13 = 138.5°
o r 360 – 138.5 = 71.5°
Directions: Read the following information to answer the question.
If A travels a distance x before meeting, B travels 27 + 27 – x = 54 – x.
Since the distances are traveled in the same time.
x/(54 – x) = 5/7.⇒ x = 22.5 Km.
Directions: Read the following information to answer the question.
Sa/Sb = √(tb/ta)
tb/ta = 36:1
Total time is 111 sec, hence time taken by A is 3 sec to reach B' and he travels
60 × 3 = 180 m. Meanwhile, B travels 3 ×10 = 30 m away from station B'.
So, to meet each other, they require (180 + 30)/(60 – 10) = 210/50 = 4.2
sec. After their first meet, they meet after 3 + 4.2 = 7.2 sec.
Directions: Read the following information to answer the question.
Since difference of 8 minutes comes in 36 hrs
∴ Difference of 15 minutes will come in 36/8 × 15 = 67.5 hr
So 7.30 am of Saturday.