Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
R C O O B Y
+ N O O O
---------------------
B U R T E N
Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve.
How?
Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1).
In the first column from right, B is directly beneath R. R will be added to nothing. In order to make R and B different, carry of 1 should be added to R as no other carry is possible. Now, from where this carry will come ? U is directly beneath C and C will be added to nothing. So, C will also have a carry of 1.
Now, there is only one possibility. Carry of 1 should be added to 9 to generate a carry of 1 (as 9+1=10). So, C= 9 and U=0 as C will have a carry of 1. This will generate carry of 1 which will be added to R.
Now on solving the value of "O" by hit and trial method. The values of alphabets are as follows:
B=2, R=1, U=0, C=9, N=7, O=4, T=8, E=6.
Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
R C O O B Y
+ N O O O
---------------------
B U R T E N
Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve.
How?
Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1).
In the first column from right, B is directly beneath R. R will be added to nothing. In order to make R and B different, carry of 1 should be added to R as no other carry is possible. Now, from where this carry will come ? U is directly beneath C and C will be added to nothing. So, C will also have a carry of 1.
Now, there is only one possibility. Carry of 1 should be added to 9 to generate a carry of 1 (as 9+1=10). So, C= 9 and U=0 as C will have a carry of 1. This will generate carry of 1 which will be added to R.
Now on solving the value of "O" by hit and trial method. The values of alphabets are as follows:
B=2, R=1, U=0, C=9, N=7, O=4, T=8, E=6.
Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
R C O O B Y
+ N O O O
---------------------
B U R T E N
Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve.
How?
Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1).
In the first column from right, B is directly beneath R. R will be added to nothing. In order to make R and B different, carry of 1 should be added to R as no other carry is possible. Now, from where this carry will come ? U is directly beneath C and C will be added to nothing. So, C will also have a carry of 1.
Now, there is only one possibility. Carry of 1 should be added to 9 to generate a carry of 1 (as 9+1=10). So, C= 9 and U=0 as C will have a carry of 1. This will generate carry of 1 which will be added to R.
Now on solving the value of "O" by hit and trial method. The values of alphabets are as follows:
B=2, R=1, U=0, C=9, N=7, O=4, T=8, E=6.
Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
R C O O B Y
+ N O O O
---------------------
B U R T E N
Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve.
How?
Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1).
In the first column from right, B is directly beneath R. R will be added to nothing. In order to make R and B different, carry of 1 should be added to R as no other carry is possible. Now, from where this carry will come ? U is directly beneath C and C will be added to nothing. So, C will also have a carry of 1.
Now, there is only one possibility. Carry of 1 should be added to 9 to generate a carry of 1 (as 9+1=10). So, C= 9 and U=0 as C will have a carry of 1. This will generate carry of 1 which will be added to R.
Now on solving the value of "O" by hit and trial method. The values of alphabets are as follows:
B=2, R=1, U=0, C=9, N=7, O=4, T=8, E=6.
Directions: In this Question , Each Alphabet used is for a distinct digit & the equation given is mathematically true .
Explanation:
R C O O B Y
+ N O O O
---------------------
B U R T E N
Here, different alphabets signify different digits. So, in order to find the value of the alphabets, we have to solve.
How?
Note: 2 single digit number makes a minimum as well as maximum carry of 1 (e.g. 9+9=18 carry 1).
In the first column from right, B is directly beneath R. R will be added to nothing. In order to make R and B different, carry of 1 should be added to R as no other carry is possible. Now, from where this carry will come ? U is directly beneath C and C will be added to nothing. So, C will also have a carry of 1.
Now, there is only one possibility. Carry of 1 should be added to 9 to generate a carry of 1 (as 9+1=10). So, C= 9 and U=0 as C will have a carry of 1. This will generate carry of 1 which will be added to R.
Now on solving the value of "O" by hit and trial method. The values of alphabets are as follows:
B=2, R=1, U=0, C=9, N=7, O=4, T=8, E=6.