If m and n are integers such that (\sqrt{2}))19 34 42 9m 8n = 3n 16m (?64) then m is
Let x and y be positive real numbers such that log5(x + y) + log5(x ? y) = 3, and log2y ? log2x = 1 ? log23. Then xy equals
The real root of the equation 26x + 23x+2 - 21 = 0 is