If minimum value of f(x) = x2 + 2bx + 2c2 is greater than the maximum value of g(x) = -x2 - 2cx + b2, then for real value of x.
For a > b > c > 0, the minimum value of the function f(x) = |x - a| + |x - b| + |x - c| is
Let f(x) = x2 and g(x) = 2x, for all real x. Then the value of f(f(g(x)) + g(f(x))) at x = 1 is
Let f(x) = 2x – 5 and g(x) = 7 – 2x. Then |f(x) + g(x)| = |f(x)| + |g(x)| if and only if