Directions: Read the following information to answer the question.
Directions: Read the following information to answer the question.
A got 36 marks but falls short of pass marks by 68%.
Maximum possible score is N.
Pass mark is 45% of N. 32% of 45% of N = 36 => N = 250
Directions: Read the following information to answer the question.
Let no. of Fishes on earlier day = x
60 fishes are tagged, out of which 25% have died/moved
remaining fishes that are tagged = 45
No. of fishes on day of second observation = 5/4x
No. of fishes caught = 70
No. of Fishes tagged = 3 = 4.2857% (3/70)
Total No. fishes on Second day of Observation = 45/.042857 (45*70/3) = 1050
No of Fishes on earlier day = x = 4/5*1050 = 840
Directions: Read the following information to answer the question.
q = α–2 and pq = –α – 1
(p + q)2 = p2 + q2 + 2pq,
Thus (α–2)2 = p2 + q2 + 2(–α– 1)
p2 + q2 = α2 – 4α + 4 + 2α + 2
p2 + q2 = α2 – 2α + 6
p2 + q2 = α2 – 2α + 1 + 5
p2 + q2 = (α – 1)2 + 5
Thus, minimum value of p2 + q2 is 5.
Directions: Read the following information to answer the question.
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The graph lies in 2nd and 3rd consider x?y? = -1 ⇒ x = - 1/?y?. This is the only option which admits x negative. |