Directions: Read the following information to answer the question.
If the three odd numbers are a - 2, a and a + 2, then 3(a - 2) = 3 + 2(a + 2)
so a + 2 = 15.
Directions: Refer the following data to answer the questions given below.
Let the quantity of the wine in the cask originally be x litres.
Using formula:
Final Amount of solute that is not replaced= Initial Amount ×(Vol. after removal/Vol. after replacing)n
Or
Final ratio of solute not replaced to total = Initial ratio ×(Vol. after removal/Vol. after replacing)n
Then ratio of wine to total solution in cask after 4 operations:
⇒1×(x−8/x)4=16/81
(considering 2nd formula here)
⇒ (x−8)/x=2/3
⇒ 3x−24=2x
⇒ x=24 litres.
Directions: Refer the following data to answer the questions given below.
S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.
C.P. of 1 kg of the mixture = Rs.{100/110}x 68.20= Rs. 62
Directions: Refer the following data to answer the questions given below.
Here, CP of unit quantity of Dearer = 460 per kg ,
CP of unit quantity of Cheaper = 410 per kg
So we can use above formulas :
Quantity of cheaper/Quantity of dearer =
{C.P of dearer-Mean price}/{Mean price-C.P of cheaper}
460-430/430-410=30/20=3/2
Directions: Refer the following data to answer the questions given below.
