If the three odd numbers are a - 2, a and a + 2, then 3(a - 2) = 3 + 2(a + 2) so a + 2 = 15.

Let the quantity of the wine in the cask originally be x litres.

Using formula: 

Final Amount of solute that is not replaced= Initial Amount ×(Vol. after removal/Vol. after replacing)n

                                                                                       Or

Final ratio of solute not replaced to total = Initial ratio ×(Vol. after removal/Vol. after replacing)n

Then ratio of wine to total solution in cask after 4 operations:

⇒1×(x−8/x)4=16/81

 (considering 2nd formula here)

⇒ (x−8)/x=2/3

 ⇒ 3x−24=2x

⇒ x=24 litres.

S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.

C.P. of 1 kg of the mixture = Rs.{100/110}x 68.20= Rs. 62   

Here, CP of unit quantity of Dearer = 460 per kg , 

CP of unit quantity of Cheaper = 410 per kg 

So we can use above formulas : 

Quantity of cheaper/Quantity of dearer =

{C.P of dearer-Mean price}/{Mean price-C.P of cheaper}

460-430/430-410=30/20=3/2